Arrange the following compounds in the increasing order of their basic…

CBSEC Chemistry class 12 question and answer | Arrange the following compounds in the increasing order of their basic strength in gaseous phase : C2H5NH2,(C2H5)3N,(C2H5)2NH

By
Komal Kohli
-
cbse

Arrange the following compounds in the increasing order of their basic strength in gaseous phase :
C2H5NH2,(C2H5)3N,(C2H5)2NH

Ans.

To determine the increasing order of basic strength of the given compounds in the gaseous phase, we need to consider the structures and steric hindrance effects of the compounds.

The basic strength of an amine depends on the availability of the lone pair of electrons on the nitrogen atom. Generally, the greater the availability of the lone pair, the stronger the base.

Here are the structures of the given compounds:

  1. �2�5��2 (Ethylamine)

  2. (�2�5)3� (Triethylamine)

  3. (�2�5)2�� (Diethylamine)

Now, let’s analyze:

  • Ethylamine (�2�5��2): It is a primary amine with one ethyl group attached to the nitrogen atom. There is no steric hindrance around the nitrogen atom, so the lone pair is readily available for donation. Thus, it is the strongest base among the given compounds.

  • Diethylamine ((�2�5)2��): It is a secondary amine with two ethyl groups attached to the nitrogen atom. The presence of two ethyl groups causes some steric hindrance around the nitrogen atom, reducing the availability of the lone pair compared to ethylamine. Therefore, it is weaker than ethylamine.

  • Triethylamine ((�2�5)3�): It is a tertiary amine with three ethyl groups attached to the nitrogen atom. Tertiary amines have the most steric hindrance around the nitrogen atom among the given compounds, which further reduces the availability of the lone pair. Thus, it is the weakest base among the given compounds.

Therefore, the increasing order of basic strength in the gaseous phase is: �2�5��2>(�2�5)2��>(�2�5)3�

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